Find the ratio in which the line segment joining the points (-3,10)(6,-8)is divided by (-1,6)
Answers
Answered by
5
Step-by-step explanation:
let the required ratio be k:1
- 1 = k(6) +1(-3)÷ k+1
-1(k+1) = 6k -3
-k-1 = 6k-3
6k+k=3-1
7k= 2
k:1 = 2:7
ratio = 2:7
Answered by
5
Step-by-step explanation:
let the required ratio be k:1
- 1 = k(6) +1(-3)÷ k+1
-1(k+1) = 6k -3
-k-1 = 6k-3
6k+k=3-1
7k= 2
k:1 = 2:7
ratio = 2:7
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