Question

Find the ratio in which the line segment joining the points A (3,-3) and B (-2,7) is divided by x axis find the oordinates of the point of division

Answer 1

Hi there....

Let the point dividing AB be X(x,0);ratio of division = m:n
X(x,0)=(3m+(-2)n)/m+n,((-3)m+7n)/m+n
=>0=-3m+7n/m+n
0=-3m+7n
3m=7n
m:n=7:3

=>x=3 x 7 + (-2) x 3 / 7+3
x=21-6/1p
x=15/10=1.5

Please comment if any doubt.....
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Answer 2

Answer:

Step-by-step explanation:

Let the ratio is 1:k

If the line divided by x-axis so the coordinate are (y, 0)

By using section formula

(y, 0)=1*-2 +k*3 ÷1+k., 1*7 +k*-3 ÷1+k

= -2+3k ÷1+k. ,7-3k ÷1+k

7-3k /1+k =0

7-3k =0

3k=7

K=7/3

-2+3(7/3) /1+7/3

-2+7 / 10÷3

5/10÷3

5*3/10

15/10

1.5