Question

find the ratio in which the line segment joining the points (-3,10) and (6,-8) is divided by(-1,6)​

Answer 1

Answer:

the section formula, if a point (x,y) divides the line joining the points

(x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then (x,y)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

Let the ratio be k:1

Substituting (x

1

,y

1

)=(−3,10) and (x

2

,y

2

)=(6,−8) in the section

formula, we get (

k+1

k(6)+1(−3)

,

k+1

k(−8)+1(10)

)=(−1,6)

(

k+1

6k−3

,

k+1

−8k+10

)=(−1,6)

Comparing the x - coordinate,

k+1

6k−3

=−1

=>6k−3=−k−1

7k=2

k=

7

2

Hence, the ratio is 2:7

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Answer 2

HIII MATE.... ur answer is attached...