Question

Find the ratio in which the line segment joining the points (-3,10)

and (6,-8) is divided by (-1,6) .​

Answer 1

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

Find the ratio in which the line segment joining the points (-3,10)

and (6,-8) is divided by (-1,6) .

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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Using the section formula, if a point (x,y) divides the line joining the points.

(x,y) and (X2,y2) in the ratio m:n,then

$= > (x , y) = ( \frac{mx2 + nx1}{m + n} , \frac{my2 + ny1}{m + n} )$

Let the ratio be k:1

substituting (x,y)=(,3,10)

$(x2,y2) = (6, - 8)$

By using section formula we get:-

$\frac{k(6) + 1( - 3)}{k + 1} , \frac{k( - 8) + 1(10}{k + 1}$

$= > \frac{6k - 3}{k + 1} , \frac{ - 8k + 10}{k + 1} = ( - 1,6)$

comparing the x-coordinate:-

$= > \frac{6k - 3}{k + 1} = - 1$

$= > 6k - 3 = - k - 1$

$= > 7k = 2$

$= > k = \frac{2}{7}$

Hence,the ratio is 2:7.

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Answer 2

HIII MATE.... ur answer is attached...