Find the ratio in which the line segment joining the points A(3,-6) and B(5,3) is divided by x axis
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Answered by
31
the ratio will be 2:1
Since the line segment is divided by x axis
therefore the point at which it get divided is (x,0)
now, let the ratio be k:1
(x,0)=[5k+3/k+1 ,3k-6/k+1]
taking ,0=3k-6/k+1
we get , 3k-6=0
3k=6
k=2
putting the value of k in k:1
we get the ratio 2:1
Since the line segment is divided by x axis
therefore the point at which it get divided is (x,0)
now, let the ratio be k:1
(x,0)=[5k+3/k+1 ,3k-6/k+1]
taking ,0=3k-6/k+1
we get , 3k-6=0
3k=6
k=2
putting the value of k in k:1
we get the ratio 2:1
Msd11111:
plz can you wtite steps
Answered by
4
Answer:2:1
Step-by-step explanation:
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