Question

find the ratio in which the line segment joining the points A(3,-6) and B(5,3) is divided by x axis

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

The ratio in which the line segment joining the given points is 2:1

Solution:

Let us assume that the line AB is divide by x axis in the ratio of $k : 1$

So the points will be $\left(\frac{5 k+3}{k+1}\right),\left(\frac{3 k-6}{k+1}\right)$

As the point lies on x axis,  

$\frac{(3 k-6)}{(k+1)}=0$

$(3 k-6)=0 \times(k+1)$

$(3 k-6)=0$

$3 k=6$

$k=\frac{6}{3}$

$k=2$

Hence the ratio in which the line segment joining the given points is 2:1