Question

: Find the ratio in which the line segment joining the points (– 3, 10) and (6, – 8) is divided by (– 1, 6).

Answer 1

3:10

same exact answer because 3 is a prime number and 10 is not in 3.

2)

6:8

3:4

please make me brainlest for my hard work

Answer 2

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•Step by step explanation:-

Here x₁ = -3, y₁ = 10, x₂ = 6, y₂ = -8  

         [m(6) + n (-3)]/(m+n) , [m (-8) + n (10)]/(m+n) = (-1,6) 

        (6m - 3n)/(m+n), (-8m+10n)/(m+n) = (-1,6)

 equating the coefficients of x and y

    (6m-3n)/(m+n) = -1       (-8m+10n)/(m+n) = 6

      →6m -  3n = -1 (m+n)

     →6m - 3n = -1 (m+n)

    →  6m-3n=-m-n

      → 6m+m= -n+3n

       →7m=2n

        →m/n= 2/7

        →m:n = 2:7

So the point (-1,6) is dividing the line segment in the ratio 2:7.