Find the ratio in which the line segment joining the points (-3, 10) and (6,-8) is divided by (-1, 6)
Answers
Answered by
1
Answer:
ratio is 2:7
Step-by-step explanation:
Using the section formula, if a point (x,y) divides the line joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n, then
(x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
Let the point P(−1,6) divides the line joining A(−3,10) and (6,−8) in the ratio k:1
Then, by section formula,
the coordinates of P are (
k+1
6k−3
,
k+1
−8k+10
)
⇒(−1,6)=(
k+1
6k−3
,
k+1
−8k+10
)
∴
k+1
6k−3
=−1
⇒6k−3=−k−1
⇒6k+k=3−1
⇒7k=2
∴ k=
7
2
Hence, the point P divides AB in the ratio 2:7
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