Math, asked by sarthak31506, 1 month ago

find the ratio in which the line segment joining the points (2,3) and (-4,5) is divided by the y axis also find the coordinates of the point of division​

Answers

Answered by tyrbylent
3

Answer:

1 : 2 ; ( 0 , \frac{11}{3} )

Step-by-step explanation:

If a point ( x , y ) divides the line segment joining the points ( x_{1} , y_{1} ) and ( x_{2} , y_{2} ) in the ratio m : n , then ( x , y ) = ( \frac{mx_{2} +nx_{1} }{m+n} , \frac{my_{2} +ny_{1} }{m+n} )

~~~~~~~~~~~~

( 2 , 3 )

( - 4 , 5 )

( x , y ) = ( \frac{-4m+2n}{m + n} , \frac{5m+3n}{m+n} ) , as the point lies on y-axis, x-coordinates equals to 0 ⇒ \frac{-4m+2n}{m + n} = 0 ⇒ - 4m + 2n = 0

4m = 2n ⇒ m : n = 1 : 2

( 0 , \frac{5+6}{3} ) = ( 0 , \frac{11}{3} )

Answered by geethauk
0

Answer:

1 : 2 ; ( 0 , )

Step-by-step explanation:

If a point ( x , y ) divides the line segment joining the points ( , ) and ( , ) in the ratio m : n , then ( x , y ) = ( , )

~~~~~~~~~~~~

( 2 , 3 )

( - 4 , 5 )

( x , y ) = ( , ) , as the point lies on y-axis, x-coordinates equals to 0 ⇒ = 0 ⇒ - 4m + 2n = 0

4m = 2n ⇒ m : n = 1 : 2

( 0 , ) = ( 0 , )

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