Find the ratio in which the line segment joining the points (-3,10) and (6,-8) id divided by(-1,6)
Answers
Answered by
2
Let ratio be k:1
By section formula
(-1,6)=(6k-3/k+1,-8k+10/k+1)
Equating
6k-3/k+1=-1
6k-3=-1(k+1)
6k=-k-1+3
7k=2
K=2/7
Ratio =2:7
By section formula
(-1,6)=(6k-3/k+1,-8k+10/k+1)
Equating
6k-3/k+1=-1
6k-3=-1(k+1)
6k=-k-1+3
7k=2
K=2/7
Ratio =2:7
Answered by
4
HIII MATE.... ur answer is attached...
Attachments:
Similar questions