find the ratio in which the line segment joining the points (- 3, 10) and (6 ,- 8) is divided by(-1,6)
Answers
Answered by
34
Answer: 2:7
Step-by-step explanation: Let the ratio in which the line segment joining ( -3, 10) and (6, -8) is divided by point ( -1, 6) be k : 1.Therefore, -1 = 6k-3/k+1
-k - 1 = 6k -3
7k = 2
k = 2/7
Therefore, the required ratio is 2:7.
Answered by
37
let ratio be (K, 1)
by section formula
6k+(-3)/k+1 , -8k +10/k+1 = -1,6
6k-3/k+1 , -8k+ 10/ k+1 = -1,6
by comparing
6k - 3/ k+1 = -1
6k -3 = -k -1
7k = 2
K = 2/7
ratio = 2/7 , 1
HOPE IT WILL HELP YOU
by section formula
6k+(-3)/k+1 , -8k +10/k+1 = -1,6
6k-3/k+1 , -8k+ 10/ k+1 = -1,6
by comparing
6k - 3/ k+1 = -1
6k -3 = -k -1
7k = 2
K = 2/7
ratio = 2/7 , 1
HOPE IT WILL HELP YOU
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