Find the ratio in which the line segment joining the points ( - 3, - 4 ) and ( 1, - 2 ) is divided by y- axis ?
Answers
HEY MATE
if a line segment is divided by y axis ,then:
A P B
' ---------------------------'----------------------------'
(-3,-4) (0,y) (1,-2)
k:1
now
let the ratio be k : 1
BY SECTION FORMULA
So, the coordinates of the point P(x, y) which divides the line segment joining the points A(x1, y1) and B(x2, y2), internally, in the ratio m1 : m2 are
P(x,y) = { (m1x2 + m2x1)/(m1 + m2 ) , (m1y2 + m2y1)/(m1 + m2 ) }
P(0,y) = { (k[1] + 1[-3] / k+1 ) , k[-2] + 1[-4] / k+1) }
={ k -3 /k+1} , {-2k -4 / k+1}
-----------comparing x axis--------------
0 = k-3/k+1
k = 3
SO THE RATIO IS 3 : 1
u can also find the point in which the ratio divides the 2 points
BY COMPARING y-axis
BUT QUESTION HAS ASKED FOR RATIO
SO U WILL NOT FIND THE POINT AS IT IS NOT ASKED
:-) :-) :-) :-) :-)
hopes this helps
PLZ MARK AS BRILLIANEST
Step-by-step explanation:
answe is 3:1 explained in attachment