Question

Find the ratio in which the line segment joining the points ( 4, 8, 10 ) and ( 6, 10, -8 ) is divided by the YZ- plane.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

2:3

Step-by-step explanation:

To find the ratio in which the line segment joining the points A ( 4, 8, 10 ) and B ( 6, 10, -8 ) is divided by the YZ- plane,

Let us assume that YZ- plane divides the line segment joining points A and B in k:1

Now apply section formula;

$x = \frac{kx_{2} + x_1}{k + 1}$

we know that x=0 in YZ-plane,so

$0= \frac{6k + 4}{k + 1} \\ \\ 6k + 4= 0 \\ \\ 6k = - 4 \\ \\ k = \frac{ - 4}{6}$

but we know that ratio can never be negative,that indicates YZ-plane divides the line segment externally,so,apply external division Formula

$0= \frac{6k - 4}{k - 1} \\ \\ 6k - 4= 0 \\ \\ 6k = 4 \\ \\ k = \frac{ 4}{6} \\ \\ \frac{k}{1} = \frac{2}{3}$

Hope it helps you.