Question

find the ratio in which the line
$x - 3y = 0$
divides the line segment joining the points (-2,-5) and (6,3). find the coordinates of the point of intersection.
Thank you!​

Answer 1

Answer:

Step-by-step explanation:

By section formula

X=6k-2/k+1

Y=3k-5/k+1

X-3y=0

6k-2/k+1-3(3k-5/k+1)=0

6k-2/k+1-9k+5/k+1=0

6k-2-9k+15/(k+1)=0

6k-2-9k+15=0

-3k+13=0

K=13/3

Therefore obtained ratio is 13:3

Answer 2

Answer:

13:3 is your answer...........