Question

find the ratio in which the line x=0 divides line ab, a(6,8), B(-4, 6) also find coordinates of the point of intersection of ab and line x=0​

Answer 1

Step-by-step explanation:

Let ratio be k:1

Hence

m

1

=k,m

2

=1

x

1

=1,y

1

=−5

x

2

=−4,y

2

=5

Also,

x=x,y=0

Using section formula

y=

m

1

+m

2

m

1

y

2

+m

2

y

1

0=

k+1

k×5+1×(−5)

0=

k+1

5k−5

5k−5=0

5k=5

k=1

Hence, k=1

Now,

x=

m

1

+m

2

m

1

x

2

+m

2

x

1

x=

k+1

k×(−4)+1×1

x=

1+1

1×(−4)+1×1

x=

2

−3

Hence the coordinate of point P(x,0) =P(

2

−3

,0)

Answer 2

Answer:

Hope you understood!