CBSE BOARD X, asked by piyushingh8414, 11 months ago

Find the ratio in which the line x-y-2=0 divide the line segemnt joining point ( 3 ; -1) and (8;9)

Answers

Answered by eshankharya
2

Answer:

2:3

Explanation:

Since the line follows the equation x-y-2 = 0, all points in the line must follow the condition: y = x-2

Therefore, every point will be of the form (x, x-2)

Let's assume a point (x, x-2) divides the line in a ratio of k:1

Using section formula:

x = (8k + 3)/(k+1) ..................................... (i)

x-2 = (9k - 1)/(k+1) ................................... (ii)

(i) - (ii):

2 = (8k + 3 - 9k + 1) / (k+1)

2 = (4 - k)/(k+1)

2k + 2 = 4 - k

3k = 2

k = 2/3

ratio is k:1

2/3:1

2:3

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