Question

find the ratio in which the point (11, 15) divides the segment joining the pounts (15, 5) and (9, 20)​

Answer 1

Answer:

Let the point P(11,15) divide the line segment AB in the ratio m₁:m₂

A = (15,5) ==> x₁ = 15 , y₁ = 5

A = (9,20)  ==> x₂ = 9 , y₂ = 20

P = (11,15) ==> x = 11 , y = 15

Here is the formula :-

x = \frac{ m_{1} x_{2} + m _{2}x_{1} }{m_{1}+ m _{2} }m1+m2m1x2+m2x1 

11 = \frac{ 9m_{1} + 15m _{2} }{m_{1}+ m _{2} }m1+m29m1+15m2 

11(m₁ + m₂) = 9m₁ + 15m₂

11m₁ + 11m₂ =  9m₁ + 15m₂

2m₁ = 4m₂

m₁/m₂ = 4/2

m₁/m₂ = 2/1

The ratio is 2:1