Question

Find the ratio in which the point (2, 5) divides the line segment joining the points (0, 1) and (6, 13).

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Answer 1

Answer:

Let m:n=k:1

Step-by-step explanation:

K : 1

.____________.____________.

A(0,1) P(2,5) B(6,13)

P(2,5)= [6K + 0 / k + 1, 13K + 1 / K+1]

= [ 6K/K+1, 13K + 1 / K+1]

2= 6K/K+1 5=13K + 1 / K+1

2K + 2 = 6K 5K + 5 = 13K + 1

4K = 2 8K = 4

K = 1 / 2 K = 1 / 2

m:n= 1/2:1

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Answer 2

Answer

Step-by-step explanation:

The point which lies on the perpendicular bisector of the line segment joining the points A (–2, – 5) and B (2,5) is (a) (0, 0) (b) (0,2) (c) (2,0) (d)d ... line segment joining the point A (1, 5) and B (4, 6) cuts the y-axis at (a) (0, 13) (b) (0 ... Find the ratio in which the point –2 –20 2 20 7 7 ,7 7 , divides the join of (–2, –2) and (2, – 4).