Find the ratio in which the point P(3/4,5/12) divides the line segment joining the points A(1/2,3/2) and B(2,-5) .
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Answered by
17
Here is the answer.
Let P(34,512) divides the line segment joining A(12,32) and B(2,−5) in the ratio of k : 1.
Now, by section formula :
34 = 2k + 12k+1 and
512 = −5k+32k+1
⇒34 = 4k+12(k+1) and
512 = −10k+32(k+1)
⇒8k+2 = 3k+3 and
−60k+18 =5k+5
⇒5k = 1 and
65k = 13
⇒k = 15 and
k =1365 = 15
So, required ratio is 1 : 5.
Let P(34,512) divides the line segment joining A(12,32) and B(2,−5) in the ratio of k : 1.
Now, by section formula :
34 = 2k + 12k+1 and
512 = −5k+32k+1
⇒34 = 4k+12(k+1) and
512 = −10k+32(k+1)
⇒8k+2 = 3k+3 and
−60k+18 =5k+5
⇒5k = 1 and
65k = 13
⇒k = 15 and
k =1365 = 15
So, required ratio is 1 : 5.
pandeyji01:
thanks for this but sorry you put wrong values
when values are these ii can solve it
yes because the values given in this question are wrong
the coordinates of A are A (1/2, 3/2) instead of (1/2, 3/12).
sorry for this my friend but values are right
because it comes in paper. read again the question
yeah i have missed the signs too
sorry
thanks for give me your time my friend
my pleasure
Answered by
2
Answer:
THE ANSWER IS 1:5
Step-by-step explanation:
let p (3/4;5/12) divides the line segment joining A(1/2) and B(2,-5) in the ratio of k:1
now, by sectional formula:
3/4=2k+ 1/2+1 and 5/12= -5+3/2k+1
=> 3/4= 4k+ 1/2(k+1) and 5/12= -10k+ 3/2 (k+1)
=>8k+2= 3k+3 and -60k+18= 5k+5
=> 5k= 1 and 6/5k=13
=> k=1/5 and k=13/65=> 1/5
therefore, required ratio is 1:5.
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