find the ratio in which the point P(3/4,5/12) divides the line segment joining the points A(1/2,3/2) and B(2,-5) .
Answers
Answered by
516
Hi ,
We know that the section formula
_____________________________________________
The point which divide the line segment
joining the points A ( x1 , y1 ) , B ( x2 , y2 ) in the ratio k:1
is P ( kx2+ x1/k +1 , ky2 + y1 / k+ 1 )
______________________________________________
According to the given problem ,
A( x1 , y1 ) = ( 1/2 , 3 /2 )
B ( x2 , y2 ) = ( 2 , -5 )
P ( x , y ) = ( 3 / 4 , 5 / 12 )
Let the ratio = k : 1
x = 3/4 ( given
(kx2 + x1 ) / ( k+ 1 ) = x
( k× 2 + 1/2 ) / ( k + 1 ) = 3 / 4
2k + 1/2 = 3 /4 ( k + 1 )
4 ( 2k + 1 / 2) = 3 ( k + 1 )
8k + 2 = 3k + 3
8k - 3 k = 3 - 2
5k = 1
k = 1/5
Therefore ,
Required ratio = k : 1
= 1 /5 : 1
= 1 : 5
P divides the line segment joining the piints A and B
in the ratio 1 : 5
I hope this helps you.
****
We know that the section formula
_____________________________________________
The point which divide the line segment
joining the points A ( x1 , y1 ) , B ( x2 , y2 ) in the ratio k:1
is P ( kx2+ x1/k +1 , ky2 + y1 / k+ 1 )
______________________________________________
According to the given problem ,
A( x1 , y1 ) = ( 1/2 , 3 /2 )
B ( x2 , y2 ) = ( 2 , -5 )
P ( x , y ) = ( 3 / 4 , 5 / 12 )
Let the ratio = k : 1
x = 3/4 ( given
(kx2 + x1 ) / ( k+ 1 ) = x
( k× 2 + 1/2 ) / ( k + 1 ) = 3 / 4
2k + 1/2 = 3 /4 ( k + 1 )
4 ( 2k + 1 / 2) = 3 ( k + 1 )
8k + 2 = 3k + 3
8k - 3 k = 3 - 2
5k = 1
k = 1/5
Therefore ,
Required ratio = k : 1
= 1 /5 : 1
= 1 : 5
P divides the line segment joining the piints A and B
in the ratio 1 : 5
I hope this helps you.
****
Answered by
261
Let the ratio be k:1
By section formula,
(2k+1/2/k+1, -5k+3/2)=(3/4,5/12)
2k+1/2/k+1=3/4 (Taking one of them)
By cross multiplication,
8k+4/2=3k+3
8k+2=3k+3
8k-3k=3-2
5k=1
K=1/5
Therefore the ratio is 1:5
I hope it helps you
Thanks
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