find the ratio in which the segment joining points (1,-3 and (4,5) is divided by x-axis? also find the coordinate of this point on x-axis
Answers
Answer: Ratio is 3:5 internally
Step-by-step explanation:
Let the point on X-axis be P (x,0) since the y-coordinate is always zero on x - axis.
Given A(1, -3) and B(4,5)
Let P divides the line joining the given points (1, -3) and (4, 5) in the ratio m : 1
The coordinates of P = (mx2 + x1 / m +1 , my2 + y1 / m + 1)
i.e. (x, 0 ) = ( 4m +1/ m+1 , 5m -3/ m+1)
By comparing both the sides, we get
5m -3/ m+1 = 0
5m-3 = 0
=> 5m = 3
m = 3/5
m:1 = 3/5 :1
= 3:5
Therefore, P divides the line segment joining two points in the ratio 3:5 internally.
Answer:
Step-by-step explanation:
Let the point on X-axis be P (x,0) �since the y-coordinate is always zero on x - axis.
Given A(1, -3) and B(4,5)
Let P divides the line joining the given points (1, -3) and (4, 5) in the ratio m : 1
The coordinates of P = (mx2 + x1 / m +1 , my2 + y1 / m + 1)
i.e. (x, 0 ) = ( 4m +1/ m+1 , 5m -3/ m+1)
By comparing both the sides, we get
5m -3/ m+1 = 0
5m-3 = 0
=> 5m = 3
m = 3/5
m:1 = 3/5 :1
= 3:5
Therefore, P divides the line segment joining two points in the ratio 3:5 internally.