Math, asked by amankashyap28, 1 year ago

find the ratio in which the segment joining points (1,-3 and (4,5) is divided by x-axis? also find the coordinate of this point on x-axis ​

Answers

Answered by Jasleen0599
232

Answer: Ratio is 3:5 internally

Step-by-step explanation:

Let the point on X-axis be P (x,0)  since the y-coordinate is always zero on x - axis.

Given A(1, -3) and B(4,5)

Let P divides the line joining the given points (1, -3) and (4, 5) in the ratio m : 1

The coordinates of   P = (mx2 + x1 / m +1 , my2 + y1 / m + 1)

i.e. (x, 0 ) = ( 4m +1/ m+1 , 5m -3/ m+1)

By comparing both the sides, we get

5m -3/ m+1 = 0

5m-3 = 0

=> 5m = 3

    m = 3/5

   m:1 = 3/5 :1

         = 3:5

Therefore, P divides the line segment joining two points in the ratio 3:5 internally.

Answered by Safsan
32

Answer:

Step-by-step explanation:

Let the point on X-axis be P (x,0) �since the y-coordinate is always zero on x - axis.

Given A(1, -3) and B(4,5)

Let P divides the line joining the given points (1, -3) and (4, 5) in the ratio m : 1

The coordinates of   P = (mx2 + x1 / m +1 , my2 + y1 / m + 1)

i.e. (x, 0 ) = ( 4m +1/ m+1 , 5m -3/ m+1)

By comparing both the sides, we get

5m -3/ m+1 = 0

5m-3 = 0

=> 5m = 3

   m = 3/5

  m:1 = 3/5 :1

        = 3:5

Therefore, P divides the line segment joining two points in the ratio 3:5 internally.

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