Question

find the ratio in which the straight line3x-4y=7 divides the join of(-2,7) and (-1,3)​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Here your answer is

Step-by-step explanation:

The ratio in which the line 3x + 4y = 7 divides the line segment joining the points (1, 2) and (-2, 1) is 4:9.

Given line is

3x + 4y - 7 = 0

a = 3, b = 4, c = -7

Given points are (x_{1},y_{1})=(1,2) (x_{2},y_{2})=(-2,1)(x

1

,y

1

)=(1,2)(x

2

,y

2

)=(−2,1)

The ratio in which the line ax + by + c = 0 divides the line segment joining the points (x_{1},y_{1}), (x_{2},y_{2})(x

1

,y

1

),(x

2

,y

2

) is

m:n=(ax_{1}+by_{1}+c):(ax_{2}+by_{2}+c)m:n=(ax

1

+by

1

+c):(ax

2

+by

2

+c)

m:n = (3(1) + 4(2) - 7):(3(-2) + 4(1) - 7)

m:n = (3 + 8 - 7):(-6 + 4 - 7)

m:n = 4:9

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