Question

Find the ratio in which the x axis divides the line segment joining the points (1, 2 )and (-2,5)

Answer 1

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Answer 2

The x-axis divides the line segment externally in the ratio 2:5.              

Step-by-step explanation:

We are given the following in the question:

x axis divides the line segment joining the points (1, 2 )and (-2,5).

Let the point be (x,0)

Section formula:

$\text{Let (x,y) divide the line segment in ration m:n}\\\\(x,y) = (\dfrac{mx_2 + nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n})$

Putting the values, we get:

$(1,2), (-2,5)\\\\(x,0) = (\dfrac{-2m + n}{m+n}, \dfrac{5m+2n}{m+n})\\\\ 0 = \dfrac{5m+2n}{m+n}\\\\5m + 2n = 0\\\\\dfrac{m}{n} = \dfrac{-2}{5}$

The x-axis divides the line segment externally in the ratio 2:5.

#LearnMore

Find coordinates of point which divides line segment joining point (3,-1)&(-2,5) in ratio 1:2.

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