Question

Find the ratio in which the Y-axis divides the line segment joining the points (5,-6) and (-1,-4). Also
find the point of intersection.​

Answer 1

Answer:

${\huge\boxed{\bf{\pink{\mathfrak{Your \: answer}}}}}$

(5 , - 6 ) C. ( -1 , -4)

_______________|_________________

A. m n B

x = 5n - 1m/ m+n ------------(i)

y = -6n - 4m / m + n ----------------(¡¡)

by finding the inter section point well get the value of x and y

by mid point formulae

5 - 1/ 2 = x , - 4- 6 /2 = y

4 / 2 = x , -10 / 2 = y

by putting the value of x and y in --------(¡) , (¡¡) equation

x = 2 , y = - 5

x = 5n - 1m/ m+n ------------(i)

y = -6n - 4m / m + n ----------------(¡¡)

by crossmultiplication

2m + 2n = 5n - m

3m = 3n

m = n

y = -6n - 4m / m + n

- 5 m - 5n = -6n - 4m

-m = -n

so if we put any value in it we get m = -1 and n = -1

Answer 2

Step-by-step explanation:

(5 , - 6 ) C. ( -1 , -4)

_______________|_________________

A. m n B

x = 5n - 1m/ m+n ------------(i)

y = -6n - 4m / m + n ----------------(¡¡)

by finding the inter section point well get the value of x and y

by mid point formulae

5 - 1/ 2 = x , - 4- 6 /2 = y

4 / 2 = x , -10 / 2 = y

by putting the value of x and y in --------(¡) , (¡¡) equation

x = 2 , y = - 5

x = 5n - 1m/ m+n ------------(i)

y = -6n - 4m / m + n ----------------(¡¡)

by crossmultiplication

2m + 2n = 5n - m

3m = 3n

m = n

y = -6n - 4m / m + n

- 5 m - 5n = -6n - 4m

-m = -n

so if we put any value in it we get m = -1 and n = -1