Question

Find the ratio in which the y axis divides the line segment joining the points 5, - 6 and -1, - 4 also find the point of intersection it is the question of NCERT example 9 of chapter 7

Answer 1

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Answer 2

Let the line segment A(5, -6) and B(-1, -4) is divided at point P(0, y) by y-axis in ratio m:n

:. x = $\frac{mx2+nx1}{m+n}$ and y = $\frac{my2+ny1}{m+n}$

Here, (x, y) = (0, y); (x1, y1) = (5, -6) and (x2, y2) = (-1, -4)

So , 0 = $\frac{m(-1)+n(5)}{m+n}$

=> 0 = -m + 5n

=> m= 5n

=> $\frac{m}{n}$ = $\frac{5}{1}$

=> m:n = 5:1

Hence, the ratio is 5:1 and the division is internal.Now,

y = $\frac{my2+ny1}{m+n}$

=> y = $\frac{5(-4)+1(-6)}{5+1}$

=> y = $\frac{-20-6}{6}$

=> y = $\frac{-26}{6}$

=> y = $\frac{-13}{3}$

Hence, the coordinates of the point of division is (0, -13/3).

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