Math, asked by chintakunta1981, 8 months ago

Find the ratio in which the
y- axis divides the line segment
joining the points (5-6) and (-1,-4).
Also find the point of intersection?​

Answers

Answered by prathmeshkhode10
0

Answer:

take x=0 and section formula

Answered by BrainlyBAKA
0

Let the line segment A(5, -6) and B(-1, -4) is divided at point P(0, y) by y-axis in ratio m:n

:. x = \frac{mx2+nx1}{m+n} and y = \frac{my2+ny1}{m+n}

Here, (x, y) = (0, y); (x1, y1) = (5, -6) and (x2, y2) = (-1, -4)

So , 0 = \frac{m(-1)+n(5)}{m+n}

=> 0 = -m + 5n

=> m= 5n

=> \frac{m}{n} = \frac{5}{1}

=> m:n = 5:1

Hence, the ratio is 5:1 and the division is internal.Now,

y = \frac{my2+ny1}{m+n}

=> y = \frac{5(-4)+1(-6)}{5+1}

=> y = \frac{-20-6}{6}

=> y = \frac{-26}{6}

=> y = \frac{-13}{3}

Hence, the coordinates of the point of division is (0, -13/3).

\\\\\\

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️

Similar questions