Question

Find the ratio in which the y-axis divides the line segment joining the points (5, -6) and (-1, -4)

Answer 1

Answer:

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Step-by-step explanation:

Solution

Let the required ration be

k

:

1

k:1

Point on y axis would be form

(

0

,

y

)

(0,y)

0

=

k

(

−

8

)

+

1

(

5

)

k

+

1

0=k(−8)+1(5)k+1

∴

k

=

5

8

∴k=58

Required ratio

k

:

1

k:1

=

5

8

:

1

=58:1 or

5

:

8

5:8