Question

find the ratio in which the y-axis divides the line segment joining the point (5,-6) and (-1,-4)​

Answer 1

Answer:

Using the section formula, if a point (x,y) divides the line joining the points (x1,y1) and (x2,y2) in the ratio m:n, then 

(x,y)=(m+nmx2+nx1,m+nmy2+ny1)

Let the point on y -axis be P(0,y) and 

AP:PB=k:1

Therefore, using section formula: 

k+15×1+(−1)×k=05−k=0⟹k=5

Hence, required ratio is 5:1.

Now,

y=5+1(−4)×5+(−1)×6

   

    =6−20−6

    =3−13

Hence, point on y -axis is P(0,3−13)