Question

Find the ratio in which the y axis fivides the line segment joining the points 6,-4 and -2,-7

Answer 1

Answer:

m:n= 3:1

Step-by-step explanation:

(x1,y1)=(6,-4)

(x2,y2)=(-2,-7)

The point on y- axis is (0,y)

By section formula,

x = mx2+nx1/m+n

0 = m(-2)+n(6)/m+n

2m=6n

m:n= 3:1

Answer 2

Answer:

It is given that the y-axis divides the segment. So, let the point which divides the line segment be, (0,y))

Let the ratio be, k:1

By section formula,

0= k(-2) + 1(-4)/k+1

By cross multiplication,

0(K+1) = -2K - 4

2K = -4

K = -2

Ratio is 2:1 externally..

So, the point divides the line segment externally (negative sign) in the ratio, 2:1

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