Question

find the ratio in which X-axis divide the line segment joining (1;4);(4;-5)​

Answer 1

$\large\bold\orange{\underline{Answer:-}}$

✯ Given points are (1,4) and (4, -5)

✯ Let the ratio be k : 1

✯ Using section formula :-

$\implies$ $\large\frac{-5k+4}{k+1}$ = 0

$\implies$ - 5k + 4 = 0

$\implies$ k = $\large\frac{4}{5}$

Therefore, Ratio in which x-axis divide the line segment joining the points is $\boxed{\bold{\purple{4:5}}}$

Answer 2

Thanks for your question...

Your required answer :

Given points :

• ( 1 , 4 )
• ( 4 , -5 )

Now section formula :

$\frac{ \: (m1 \times y2) +( m2 \times y1)}{m1 + m2}$

Now , Solution :

• Let the rato be k : 1

$\frac{ - 5k + 4}{ \: \: \: k + 1} = 0 \\ \\ - 5k + 4 = 0 \\ \\ - 5k = - 4 \\ \\ k = \frac{ - 4}{ - 5} \\ \\ k = \frac{4}{5}$

Therefore X-axis divide the line segment joining in 4 : 5 .

Brainliest Please