Question

Find the ratio in which x-axis divides the line segment joining the points 3, 3 and 6,-6

Answer 1

Answer:

The required ratio is 1:2

Answer 2

The x-axis divides the line segment in the ration 1:2                                    

Step-by-step explanation:

We are given the following in the question:

Coordinates of line segment are (3,3) and (6,-6)

Let the x axis divide the line segment in the ratio k:1.

The point on axis will be of the form (x,0).

By section formula:

$(x,y) = (\dfrac{kx_2 + x_1}{k+1}, \dfrac{ky_2 + y_1}{k+1})$

Putting the values, we get,

$(x,0) = (\dfrac{6k + 3}{k+1}, \dfrac{-6k + 3}{k+1})\\\\0 = \dfrac{-6k + 3}{k+1}\\\\-6k + 3 = 0\\-6k = -3\\\\k = \dfrac{1}{2}$

Thus, the x-axis divides the line segment in the ration 1:2.

#LearnMore

Find the ratio in which the line joining the points(2,3) and (4,1) divides the segment joining points (1,2) and (4,3)​

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