Question

find the ratio in which y-axis divides the line segment joining the points (5,-6) and (-1,-4) . also find the point of trisection .​

Answer 1

Step-by-step explanation:

Let the point be A(5,−6), B(−1,−4) and P(0,y)

Point P is on y−axis,hence its x co-ordinate is 0.So, it is of the form P(0,y)

Now, we have to find ratio.

Let the ratio be k:1

Hence m

1

=k, m

2

=1, x

1

=5, y

1

=−6, x

2

=−1,y

2

=−4, x=0, y=0

Using sections formula x=

m

1

+m

2

m

1

x

2

+m

2

x

1

⇒0=

k+1

−k+5

∴k=5

Again y=

m

1

+m

2

m

1

y

2

+m

2

y

1

=

k+1

−4k−6

=

6

−20−6

for k=5

=

3

−13

Hence the coordiantes of point is P(0,

3

−13

)