Question

find the ratio in which y axis divides the line segment joining the points - 4 ,- 6 and 10, 12 also find the coordinates of the point of division​

Answer 1

Answer:

Step-by-step explanation:let the coordinates of the point be (0,y) and y-axis divides the line segment in the ratio k :1.

(0,y) = {(10k-4)/k+1 ,(12k-6)/k+1}

0=10k-4/k+1

10k =4

k=2/5 ==>the ratio of division is 2:5

now, y =(12k-6)/k+1

y={(12*2/5) -6}/(2/5)+1

y =-6/7

thus the coordinates of the point is (0,-6/7)

hope it helps...

Answer 2

Answer:let ratio= k:1and point coordinates are0,y

A(-4,-6)

B(10,12)

0,y=k(10)-4/(k+1), k(12)-6/(k+1)

0(k+1)=10k-4

4=10k

K=4/10=2/5

Ratio=2:5

coordinates areo,y

Y(k+1)=12k-6

Yk+ y =12k-6((k=2/5))

0.4y+y=4.8-6

1.4Y=-1.2

Y=-1.2/1.4=-6/7

Step-by-step explanation: