Question

find the ratio in which y axis divides the line segment joining (-3,6) and (12,-3)

Answer 1

Answer:

Let the point on Y axis be P(0,a).

The point on Line segment which is divided by Y axis are A (-3,6), and B (12,-3).

The point P divides Segment AB in the ratio of k:1 .

The formula for internal division if point $(x_{1},y_{1}) {\text{and}} (x_{2},y_{2})$ is divided into m:n , then

$x=\frac{mx_{2}+nx_{1}}{m+n}, y=\frac{my_{2}+ny_{1}}{m+n}$

$0=\frac{12k-3}{k+1}\\\\ 12 k-3=0\\\\12 k=3\\\\k=\frac{3}{12}\\\\k=\frac{1}{4}$

So, the ratio in which y axis, divides the line segment joining (-3,6) and (12,-3) is 1:4.

Answer 2

Step-by-step explanation:

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