Find the ratio in with the line segment joining the point A(3,-6)and B(5,3) is divided by x-axis
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THE ANSWER IS HERE
the point on x-axis is (x,0)
let x-axis divides the line segment in the ratio m:n
So, From the question.
(x,0)= [(5m+3n)/(m+n), (3m-6n)/(m+n)]
compare y-coordinates .
=> (3m-6n)/(m+n)= 0
=> 3m-6n=0
=> 3m=6n
=> m/n=6/3
=> m:n=2:1
so they x-axis divides the line segment in the ratio 2:1
:-)Hope it helps u.
THE ANSWER IS HERE
the point on x-axis is (x,0)
let x-axis divides the line segment in the ratio m:n
So, From the question.
(x,0)= [(5m+3n)/(m+n), (3m-6n)/(m+n)]
compare y-coordinates .
=> (3m-6n)/(m+n)= 0
=> 3m-6n=0
=> 3m=6n
=> m/n=6/3
=> m:n=2:1
so they x-axis divides the line segment in the ratio 2:1
:-)Hope it helps u.
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