Question

find the ratio of a6 and a8 in the geometricprogression#
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Answer 1

Answer:

Step-by-step explanation:

1/(r square)

where r is common ratio

Answer 2

Answer:

Step-by-step explanation:

(a6)×(a8)=(a7)^2

By dividing both sides with (a8)^2 then

(a6)/(a8)=[(a7)/(a8)]^2

We know that nth term of GP is a×(r)^(n-1)

So the ratio of a6 and a8 is 1/(r)^2