Question

*Find the ratio of atoms by mass in a molecule of
(a) Carbon dioxide
(b) Benzene*

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Answer 1

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$\large\underline{\underline{\red{\sf Question:-}}}$

✤ Find the ratio of atoms by mass in a molecule of

(a) Carbon dioxide

(b) Benzene

$\large\underline{\underline{\red{\sf Required\:Answer:-}}}$

$\underline{\sf \purple{Solution\:\:(a)}}$

We know that carbon dioxide is made up of Carbon and Oxygen . So the mass of

• Carbon is 12 g
• Oxygen is 16g .

In a carbon dioxide molecule ($\sf CO_2$) , 2 molecules of Oxygen combine with one molecule of carbon to form carbon dioxide.

$\underline{\tt{\pink{So,\: the\; ratio \;by\:mass;}}}$

$\sf\qquad = 12g : 2\times16g$

$\sf\qquad = 12g : 32g$

$\sf\qquad =\dfrac{1}{\cancel4}\bigg({ \cancel{12g }}\bigg): \dfrac{1}{\cancel4}\bigg({ \cancel{32g }}\bigg)$

$\qquad\boxed{\red{\bf \longmapsto 3:8}}$

$\underline{\tt{\pink{Structure\:of\:Benzene:-}}}$

$\boxed{\setlength{\unitlength}{1 cm}\begin{picture}(5,5)\put(2,1){\line(1,1){1}}\put(3,2){\line( 0,1){1.5}}\put(3,3.5){\line( - 1,1){0.97}}\put(2,4.5){\line( - 1, - 1){0.97}}\put(1,3.54){\line(0, - 1){1.52}}\put(1,2){\line(1, - 1){1}}\put(2,0.7){ \sf C }\put(3,1.7){ \sf C }\put(3,3.5){ \sf C }\put(1.9,4.6){ \sf C }\put(0.7,1.78){ \sf C }\put(0.7,3.5){ \sf C }\put(2.8,3.55){\line( - 1,1){0.8}}\put(1.1,3.5){\line( 0, - 1){1.4}}\put(2.9,2){\line( - 1, - 1){0.8}}\put(3,0.5){ \boxed{\bf Benzene } }\end{picture}}$

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$\underline{\sf \purple{Solution\:\:(b)}}$

We know that Benzene is made up of Carbon and Hydrogen . So the mass of

• Carbon is 12 g
• Hydrogen is 1g .

In a Benzene molecule ($\sf C_6H_6$) , 6 molecules of Hydrogen combine with six molecule of carbon to form Benzene.

$\underline{\tt{\pink{So,\: the\; ratio \;by\:mass;}}}$

$\sf\qquad = 12g\times6 : 1g\times6$

$\sf\qquad = 72g : 6g$

$\sf\qquad =\dfrac{1}{\cancel6}\bigg({ \cancel{72g }}\bigg): \dfrac{1}{\cancel6}\bigg({ \cancel{6g }}\bigg)$

$\qquad\boxed{\red{\bf \longmapsto 12:1}}$

$\underline{\tt{\pink{Structure\:of\: Carbondioxide:-}}}$

$\boxed{\setlength{\unitlength}{1 cm}\begin{picture}(5,3)\put(1,1){ \sf O } \put(1.3,1.2){\line(1,0){1}}\put(1.3,1){\line(1,0){1}}\put(2.4,1){ \sf C } \put(2.7,1.2){\line(1,0){1}}\put(2.7,1){\line(1,0){1}}\put(3.8,1){ \sf O } \put(1.2,2.5){ \boxed{\bf Carbondioxide} }\end{picture}}$

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