Find the ratio of de broglie wavelength of molecules of hydrogen and helium which are at temperature 27° celsius and 1 27 degree celsius respectively
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Hello Dear,
◆ Answer -
λ(H2) : λ(He) = √4 : √3
◆ Explaination -
# Given -
M1 = 2 g/mol
M2 = 2 g/mol
T1 = 27 ℃ = 300 K
T2 = 127 ℃ = 400 K
# Solution -
Ratio of de Broglie wavelength of H2 to He is given by -
λ1 / λ2 = √(M2.T2 / M1.T1)
λ1 / λ2 = √(2×400 / 2×300)
λ1 / λ2 = √(4/3)
Therefore, ratio of de Broglie wavelengths of H2 & He is √4 : √3 .
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