find the ratio of distance and displacement when a car completes 3.5 rounds of circular track of radius 100m
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Answered by
4
its distance is 3.5*(2πr).
=7πr metre
=700π m
its displacement is distance of final positions and initial position.
ie. 2r=2*100=200m.
so ratio=700π/200=3.5π
=7πr metre
=700π m
its displacement is distance of final positions and initial position.
ie. 2r=2*100=200m.
so ratio=700π/200=3.5π
Answered by
2
Answer:
11:1
Explanation:
r=100m
2πr=44/7 x 100 = 4400/7
distance= 4400/7 x 35/10 = 2200m
displacement = πr = 200m
2200:200 = 11:1
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