Question

Find the ratio of distance traveled in 3 rd and 5th sec traveling with an acceleration of 2m/s^2 starting from rest.​

Answer 1

Answer:

Given,

a=10m/s2

u=0m/s

t=5sec

From 2nd equation of motion,

S=ut+21at2

S=0×5+21×10×5×5

S=0+125

S=125m