Question

find the ratio of equivalent resistanceof series combination of n equal resistances to the equivalent resistance in parallel combination of these n resistances​

Answer 1

Answer: The resistance of a series of n equal resistances is simply n * R

For n equal parallel resistances, it is R/n.

So the ratio is n*R / (R/n)

which equals (N^2 * R)/R

which is n^2

So the ratio of the resistance of the series string to the parallel combination is n squared, where n is the number of resistors.

For example: 4x 10R resistors in series is 40R

4x 10R resistors in parallel is 2.5R

40/2.5 = 16 which is 4 squared

Explanation: