Question

Find the Ratio of L.S.A of cube and its base Area.​

Answer 1

$\huge \underline \bold \green{QUESTION}:$

Find the Ratio of L.S.A of cube and its base Area.

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$\huge \underline \bold \red{SOLUTION}:$

$the \: LSA \: of \: a \: cube \: contains \: the \: \\ area \: of \: six \: sides \: of \: the \: cube \\ but \: its \: base \: contains \: only \: one \: bottom \: side \\ if \: LSA \: of \: cube \: is \: 6 {a }^{2} \\ then \: the \: area \: of \: base \: of \: cube \: will \: \\ be \: equal \: to \: {a}^{2} \\ therefore \: the \: ratio \: is \\ 6 {a}^{2} : {a}^{2} = 6:1$

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$\underline\bold \red{final \: answer}$

$\huge \boxed{6:1}$

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hope it helps you

thankyou

Answer 2

Answer:

ok let's assume the one leg of cube is 1,then surface area will be 6(1) ^2=6 , now the rectangular solid will be (2)(1) (1) , the areas of the solid will be 2(ab+ac+bc) thus surface area will be 2(5) =10 like the ratio of base will be 3:1, 3:2, 3:3, 3:4 according to it's side