Find the ratio of length of a closed pipe to that of the open pipe in order that the second overtone of the
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Frequency of second overtone of open pipe
V•=3v/21•
Frequency of fourth overtone of open pipe
Vc=9v/4lc
Where lc=length of the closed pipe
L•=length of an open organ pipe
3v/2l•=94/4lc
Lc/l•=3/2
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