Find the ratio of line segment A(-3,-5) B (-2,0) is divided in x axis
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Answer:
We know that by section formula, the co-ordinates of the points which divide internally the line segment joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n is
(x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
Now we have to find ratio
Let ratio be k:1
Hence
m
1
=k,m
2
=1
x
1
=1,y
1
=−5
x
2
=−4,y
2
=5
Also
x=x,y=0
Using section formula
y=
m
1
+m
2
m
1
y
2
+m
2
y
1
0=
k+1
k×5+1×(−5)
⇒0=
k+1
5k−5
⇒5k−5=0
⇒5k=5
∴k=1
Now, for x
x=
m
1
+m
2
m
1
x
2
+m
2
x
2
=
k+1
k×(−4)+1×1
=
1+1
1×(−4)+1
=
2
−4+1
=
2
−3
Hence the coordinate of point is P(x,0)=P(
2
−3
,0)
Step-by-step explanation:
please give me some point
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