Find the ratio of magnetic dipole moment and magnetic field at the centre of a disc. Radius of disc is R and it is rotating at constant angular speed o about its axis. The disc is insulating and uniformly charged
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Let surface charge density is σ.
(dq)=[(2πr)dr]σ
Equivalent current i=(dq)f
dM=iA=[(dq)f][πr2]
∴M=∫0RdM
dB=2rμoi=2rμo(dq)f
∴B=∫0RdB
Now, we can find the ratio BM
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