Question

find the ratio of mass of the component element in the following compound - lead nitrate​

Answer 1

Answer:

atomic mass of c=12u, h=1u and o=16u.

number of H atom present is 4, so mass of H atoms =4*1=4u

ch2oh

c:o:h

12:16:4

3:4:1

hence the ratio by mass of the combining elements is 3:4:1