find
the ratio of molecules present
in 11.2 lit of O2 and CH4
Answers
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1
Answer:
HERE'S YOUR ANSWER
Explanation:
no.of molecule = (6.022×10²³)/(2=3.011×10²³)
no. of atoms =( 3.011×10²³) = (6.022×10²³)
since oxygen gas is diatomic
HOPE THIS WILL HELP YOU
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