Question

find
the ratio of molecules present
in 11.2 lit of O2 and CH4​

Answer 1

Answer:

HERE'S YOUR ANSWER

Explanation:

no.of molecule = (6.022×10²³)/(2=3.011×10²³)

no. of atoms =( 3.011×10²³) = (6.022×10²³)

since oxygen gas is diatomic

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