CBSE BOARD X, asked by Anurag3007, 10 months ago

find the ratio of n even numbers to the n odd number

Answers

Answered by siya2354
1

Answer:

Sum of n even number = 2+4+6+…n

a = 2, d = 2

Sn = (n/2)(2a+(n-1)d)

= (n/2)(4+(n-1)2)

= (n/2)(2+2n)

= n(1+n)

Sum of n odd number = 1+3+5+…2n-1

a = 1, d = 2

Sn = (n/2)(2a+(n-1)d)

= ((n)/2)(2+(n-1)2)

= n2

Ratio of the sums of first n even number and n odd number = n(1+n)/n2

= (n+1)/n

HOPE IT HELPS

THANK YOU

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