Question

Find the ratio of potential energy of two objects kept at same height but mass of one object is double of other

Answer 1

potential energy = mgh
where m is mass of body
g is acceleration due to gravity
h is the height of object from ground

a/c to question,
height is same
e.g H1 = H2 = H( let )

but M1 = 2M2

so, PE1 = M1gH1 = 2M2gH
PE2 = M2gH2 =M2gH

PE1/PE2 = 2/1

Answer 2

Hi friend ,

Potential energy of an object = mgh
When mass is doubled = 2m
Potential energy when mass is doubled = 2mgh

Ratio = Potential energy of the object when mass is doubled / Potential energy of the object.

Ratio = 2mgh/ mgh

Ratio = 2/1

Ratio = 2:1
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Hope this helped u...
PLZ MARK AS BRAINLIEST....