Question

Find the ratio of rms speed of oxygen molecule to that of sulphur dioxide
molecule​

Answer 1

Answer:

sorry i am in 7 class i cant give you answer sorry bhasorry

Answer 2

Answer:

1:4

Explanation:

Root mean square velocity =

M

3RT

For SO

2

molecule, M = 64 g/mole

U

RMS

=

64

3×R×T

For Helium gas molecule, M = 4 g/mole

U

RMS

=

4

3×R×T

(U

RMS

)

He

(U

RMS

)

SO

2

= 644

= 41

=1:4